y^2=4y-5

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Solution for y^2=4y-5 equation: 



y^2=4y-5

We move all terms to the left:

y^2-(4y-5)=0

We get rid of parentheses

y^2-4y+5=0

a = 1; b = -4; c = +5;
Δ = b2-4ac
Δ = -42-4·1·5
Δ = -4
Delta is less than zero, so there is no solution for the equation

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